3.5.75 \(\int (a+b \sinh ^2(e+f x))^{3/2} \tanh ^2(e+f x) \, dx\) [475]

3.5.75.1 Optimal result
3.5.75.2 Mathematica [C] (verified)
3.5.75.3 Rubi [A] (verified)
3.5.75.4 Maple [A] (verified)
3.5.75.5 Fricas [F]
3.5.75.6 Sympy [F]
3.5.75.7 Maxima [F]
3.5.75.8 Giac [F(-2)]
3.5.75.9 Mupad [F(-1)]

3.5.75.1 Optimal result

Integrand size = 25, antiderivative size = 260 \[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\frac {4 b \cosh (e+f x) \sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{3 f}-\frac {(7 a-8 b) E\left (\arctan (\sinh (e+f x))\left |1-\frac {b}{a}\right .\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{3 f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}+\frac {(3 a-4 b) \operatorname {EllipticF}\left (\arctan (\sinh (e+f x)),1-\frac {b}{a}\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{3 f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}+\frac {(7 a-8 b) \sqrt {a+b \sinh ^2(e+f x)} \tanh (e+f x)}{3 f}-\frac {\left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh (e+f x)}{f} \]

output
4/3*b*cosh(f*x+e)*sinh(f*x+e)*(a+b*sinh(f*x+e)^2)^(1/2)/f-1/3*(7*a-8*b)*(1 
/(1+sinh(f*x+e)^2))^(1/2)*(1+sinh(f*x+e)^2)^(1/2)*EllipticE(sinh(f*x+e)/(1 
+sinh(f*x+e)^2)^(1/2),(1-b/a)^(1/2))*sech(f*x+e)*(a+b*sinh(f*x+e)^2)^(1/2) 
/f/(sech(f*x+e)^2*(a+b*sinh(f*x+e)^2)/a)^(1/2)+1/3*(3*a-4*b)*(1/(1+sinh(f* 
x+e)^2))^(1/2)*(1+sinh(f*x+e)^2)^(1/2)*EllipticF(sinh(f*x+e)/(1+sinh(f*x+e 
)^2)^(1/2),(1-b/a)^(1/2))*sech(f*x+e)*(a+b*sinh(f*x+e)^2)^(1/2)/f/(sech(f* 
x+e)^2*(a+b*sinh(f*x+e)^2)/a)^(1/2)-(a+b*sinh(f*x+e)^2)^(3/2)*tanh(f*x+e)/ 
f+1/3*(7*a-8*b)*(a+b*sinh(f*x+e)^2)^(1/2)*tanh(f*x+e)/f
 
3.5.75.2 Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 2.51 (sec) , antiderivative size = 188, normalized size of antiderivative = 0.72 \[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\frac {-8 i a (7 a-8 b) \sqrt {\frac {2 a-b+b \cosh (2 (e+f x))}{a}} E\left (i (e+f x)\left |\frac {b}{a}\right .\right )+32 i a (a-b) \sqrt {\frac {2 a-b+b \cosh (2 (e+f x))}{a}} \operatorname {EllipticF}\left (i (e+f x),\frac {b}{a}\right )+\sqrt {2} \left (-24 a^2+40 a b-13 b^2-4 (2 a-3 b) b \cosh (2 (e+f x))+b^2 \cosh (4 (e+f x))\right ) \tanh (e+f x)}{24 f \sqrt {2 a-b+b \cosh (2 (e+f x))}} \]

input
Integrate[(a + b*Sinh[e + f*x]^2)^(3/2)*Tanh[e + f*x]^2,x]
 
output
((-8*I)*a*(7*a - 8*b)*Sqrt[(2*a - b + b*Cosh[2*(e + f*x)])/a]*EllipticE[I* 
(e + f*x), b/a] + (32*I)*a*(a - b)*Sqrt[(2*a - b + b*Cosh[2*(e + f*x)])/a] 
*EllipticF[I*(e + f*x), b/a] + Sqrt[2]*(-24*a^2 + 40*a*b - 13*b^2 - 4*(2*a 
 - 3*b)*b*Cosh[2*(e + f*x)] + b^2*Cosh[4*(e + f*x)])*Tanh[e + f*x])/(24*f* 
Sqrt[2*a - b + b*Cosh[2*(e + f*x)]])
 
3.5.75.3 Rubi [A] (verified)

Time = 0.45 (sec) , antiderivative size = 326, normalized size of antiderivative = 1.25, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.360, Rules used = {3042, 25, 3675, 369, 403, 406, 320, 388, 313}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \tanh ^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \tan (i e+i f x)^2 \left (-\left (a-b \sin (i e+i f x)^2\right )^{3/2}\right )dx\)

\(\Big \downarrow \) 25

\(\displaystyle -\int \left (a-b \sin (i e+i f x)^2\right )^{3/2} \tan (i e+i f x)^2dx\)

\(\Big \downarrow \) 3675

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \int \frac {\sinh ^2(e+f x) \left (b \sinh ^2(e+f x)+a\right )^{3/2}}{\left (\sinh ^2(e+f x)+1\right )^{3/2}}d\sinh (e+f x)}{f}\)

\(\Big \downarrow \) 369

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \left (\int \frac {\sqrt {b \sinh ^2(e+f x)+a} \left (4 b \sinh ^2(e+f x)+a\right )}{\sqrt {\sinh ^2(e+f x)+1}}d\sinh (e+f x)-\frac {\sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2}}{\sqrt {\sinh ^2(e+f x)+1}}\right )}{f}\)

\(\Big \downarrow \) 403

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \left (\frac {1}{3} \int \frac {(7 a-8 b) b \sinh ^2(e+f x)+a (3 a-4 b)}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {b \sinh ^2(e+f x)+a}}d\sinh (e+f x)-\frac {\sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2}}{\sqrt {\sinh ^2(e+f x)+1}}+\frac {4}{3} b \sinh (e+f x) \sqrt {\sinh ^2(e+f x)+1} \sqrt {a+b \sinh ^2(e+f x)}\right )}{f}\)

\(\Big \downarrow \) 406

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \left (\frac {1}{3} \left (a (3 a-4 b) \int \frac {1}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {b \sinh ^2(e+f x)+a}}d\sinh (e+f x)+b (7 a-8 b) \int \frac {\sinh ^2(e+f x)}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {b \sinh ^2(e+f x)+a}}d\sinh (e+f x)\right )-\frac {\sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2}}{\sqrt {\sinh ^2(e+f x)+1}}+\frac {4}{3} b \sinh (e+f x) \sqrt {\sinh ^2(e+f x)+1} \sqrt {a+b \sinh ^2(e+f x)}\right )}{f}\)

\(\Big \downarrow \) 320

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \left (\frac {1}{3} \left (b (7 a-8 b) \int \frac {\sinh ^2(e+f x)}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {b \sinh ^2(e+f x)+a}}d\sinh (e+f x)+\frac {(3 a-4 b) \sqrt {a+b \sinh ^2(e+f x)} \operatorname {EllipticF}\left (\arctan (\sinh (e+f x)),1-\frac {b}{a}\right )}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {\frac {a+b \sinh ^2(e+f x)}{a \left (\sinh ^2(e+f x)+1\right )}}}\right )-\frac {\sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2}}{\sqrt {\sinh ^2(e+f x)+1}}+\frac {4}{3} b \sinh (e+f x) \sqrt {\sinh ^2(e+f x)+1} \sqrt {a+b \sinh ^2(e+f x)}\right )}{f}\)

\(\Big \downarrow \) 388

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \left (\frac {1}{3} \left (b (7 a-8 b) \left (\frac {\sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{b \sqrt {\sinh ^2(e+f x)+1}}-\frac {\int \frac {\sqrt {b \sinh ^2(e+f x)+a}}{\left (\sinh ^2(e+f x)+1\right )^{3/2}}d\sinh (e+f x)}{b}\right )+\frac {(3 a-4 b) \sqrt {a+b \sinh ^2(e+f x)} \operatorname {EllipticF}\left (\arctan (\sinh (e+f x)),1-\frac {b}{a}\right )}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {\frac {a+b \sinh ^2(e+f x)}{a \left (\sinh ^2(e+f x)+1\right )}}}\right )-\frac {\sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2}}{\sqrt {\sinh ^2(e+f x)+1}}+\frac {4}{3} b \sinh (e+f x) \sqrt {\sinh ^2(e+f x)+1} \sqrt {a+b \sinh ^2(e+f x)}\right )}{f}\)

\(\Big \downarrow \) 313

\(\displaystyle \frac {\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x) \left (\frac {1}{3} \left (\frac {(3 a-4 b) \sqrt {a+b \sinh ^2(e+f x)} \operatorname {EllipticF}\left (\arctan (\sinh (e+f x)),1-\frac {b}{a}\right )}{\sqrt {\sinh ^2(e+f x)+1} \sqrt {\frac {a+b \sinh ^2(e+f x)}{a \left (\sinh ^2(e+f x)+1\right )}}}+b (7 a-8 b) \left (\frac {\sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{b \sqrt {\sinh ^2(e+f x)+1}}-\frac {\sqrt {a+b \sinh ^2(e+f x)} E\left (\arctan (\sinh (e+f x))\left |1-\frac {b}{a}\right .\right )}{b \sqrt {\sinh ^2(e+f x)+1} \sqrt {\frac {a+b \sinh ^2(e+f x)}{a \left (\sinh ^2(e+f x)+1\right )}}}\right )\right )-\frac {\sinh (e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2}}{\sqrt {\sinh ^2(e+f x)+1}}+\frac {4}{3} b \sinh (e+f x) \sqrt {\sinh ^2(e+f x)+1} \sqrt {a+b \sinh ^2(e+f x)}\right )}{f}\)

input
Int[(a + b*Sinh[e + f*x]^2)^(3/2)*Tanh[e + f*x]^2,x]
 
output
(Sqrt[Cosh[e + f*x]^2]*Sech[e + f*x]*((4*b*Sinh[e + f*x]*Sqrt[1 + Sinh[e + 
 f*x]^2]*Sqrt[a + b*Sinh[e + f*x]^2])/3 - (Sinh[e + f*x]*(a + b*Sinh[e + f 
*x]^2)^(3/2))/Sqrt[1 + Sinh[e + f*x]^2] + (((3*a - 4*b)*EllipticF[ArcTan[S 
inh[e + f*x]], 1 - b/a]*Sqrt[a + b*Sinh[e + f*x]^2])/(Sqrt[1 + Sinh[e + f* 
x]^2]*Sqrt[(a + b*Sinh[e + f*x]^2)/(a*(1 + Sinh[e + f*x]^2))]) + (7*a - 8* 
b)*b*((Sinh[e + f*x]*Sqrt[a + b*Sinh[e + f*x]^2])/(b*Sqrt[1 + Sinh[e + f*x 
]^2]) - (EllipticE[ArcTan[Sinh[e + f*x]], 1 - b/a]*Sqrt[a + b*Sinh[e + f*x 
]^2])/(b*Sqrt[1 + Sinh[e + f*x]^2]*Sqrt[(a + b*Sinh[e + f*x]^2)/(a*(1 + Si 
nh[e + f*x]^2))])))/3))/f
 

3.5.75.3.1 Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 313
Int[Sqrt[(a_) + (b_.)*(x_)^2]/((c_) + (d_.)*(x_)^2)^(3/2), x_Symbol] :> Sim 
p[(Sqrt[a + b*x^2]/(c*Rt[d/c, 2]*Sqrt[c + d*x^2]*Sqrt[c*((a + b*x^2)/(a*(c 
+ d*x^2)))]))*EllipticE[ArcTan[Rt[d/c, 2]*x], 1 - b*(c/(a*d))], x] /; FreeQ 
[{a, b, c, d}, x] && PosQ[b/a] && PosQ[d/c]
 

rule 320
Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> S 
imp[(Sqrt[a + b*x^2]/(a*Rt[d/c, 2]*Sqrt[c + d*x^2]*Sqrt[c*((a + b*x^2)/(a*( 
c + d*x^2)))]))*EllipticF[ArcTan[Rt[d/c, 2]*x], 1 - b*(c/(a*d))], x] /; Fre 
eQ[{a, b, c, d}, x] && PosQ[d/c] && PosQ[b/a] &&  !SimplerSqrtQ[b/a, d/c]
 

rule 369
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_ 
), x_Symbol] :> Simp[e*(e*x)^(m - 1)*(a + b*x^2)^(p + 1)*((c + d*x^2)^q/(2* 
b*(p + 1))), x] - Simp[e^2/(2*b*(p + 1))   Int[(e*x)^(m - 2)*(a + b*x^2)^(p 
 + 1)*(c + d*x^2)^(q - 1)*Simp[c*(m - 1) + d*(m + 2*q - 1)*x^2, x], x], x] 
/; FreeQ[{a, b, c, d, e}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] && GtQ[q, 0 
] && GtQ[m, 1] && IntBinomialQ[a, b, c, d, e, m, 2, p, q, x]
 

rule 388
Int[(x_)^2/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] 
 :> Simp[x*(Sqrt[a + b*x^2]/(b*Sqrt[c + d*x^2])), x] - Simp[c/b   Int[Sqrt[ 
a + b*x^2]/(c + d*x^2)^(3/2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - 
 a*d, 0] && PosQ[b/a] && PosQ[d/c] &&  !SimplerSqrtQ[b/a, d/c]
 

rule 403
Int[((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*( 
x_)^2), x_Symbol] :> Simp[f*x*(a + b*x^2)^(p + 1)*((c + d*x^2)^q/(b*(2*(p + 
 q + 1) + 1))), x] + Simp[1/(b*(2*(p + q + 1) + 1))   Int[(a + b*x^2)^p*(c 
+ d*x^2)^(q - 1)*Simp[c*(b*e - a*f + b*e*2*(p + q + 1)) + (d*(b*e - a*f) + 
f*2*q*(b*c - a*d) + b*d*e*2*(p + q + 1))*x^2, x], x], x] /; FreeQ[{a, b, c, 
 d, e, f, p}, x] && GtQ[q, 0] && NeQ[2*(p + q + 1) + 1, 0]
 

rule 406
Int[((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*( 
x_)^2), x_Symbol] :> Simp[e   Int[(a + b*x^2)^p*(c + d*x^2)^q, x], x] + Sim 
p[f   Int[x^2*(a + b*x^2)^p*(c + d*x^2)^q, x], x] /; FreeQ[{a, b, c, d, e, 
f, p, q}, x]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3675
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2)^(p_.)*tan[(e_.) + (f_.)*(x_)]^ 
(m_), x_Symbol] :> With[{ff = FreeFactors[Sin[e + f*x], x]}, Simp[ff^(m + 1 
)*(Sqrt[Cos[e + f*x]^2]/(f*Cos[e + f*x]))   Subst[Int[x^m*((a + b*ff^2*x^2) 
^p/(1 - ff^2*x^2)^((m + 1)/2)), x], x, Sin[e + f*x]/ff], x]] /; FreeQ[{a, b 
, e, f, p}, x] && IntegerQ[m/2] &&  !IntegerQ[p]
 
3.5.75.4 Maple [A] (verified)

Time = 2.88 (sec) , antiderivative size = 414, normalized size of antiderivative = 1.59

method result size
default \(-\frac {-\sqrt {-\frac {b}{a}}\, b^{2} \sinh \left (f x +e \right )^{5}+2 \sqrt {-\frac {b}{a}}\, a b \sinh \left (f x +e \right )^{3}-4 \sqrt {-\frac {b}{a}}\, b^{2} \sinh \left (f x +e \right )^{3}-3 a^{2} \sqrt {\frac {a +b \sinh \left (f x +e \right )^{2}}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \operatorname {EllipticF}\left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right )+11 a \sqrt {\frac {a +b \sinh \left (f x +e \right )^{2}}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \operatorname {EllipticF}\left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) b -8 \sqrt {\frac {a +b \sinh \left (f x +e \right )^{2}}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \operatorname {EllipticF}\left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) b^{2}-7 \sqrt {\frac {a +b \sinh \left (f x +e \right )^{2}}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \operatorname {EllipticE}\left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a b +8 \sqrt {\frac {a +b \sinh \left (f x +e \right )^{2}}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \operatorname {EllipticE}\left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) b^{2}+3 \sqrt {-\frac {b}{a}}\, a^{2} \sinh \left (f x +e \right )-4 \sqrt {-\frac {b}{a}}\, a b \sinh \left (f x +e \right )}{3 \sqrt {-\frac {b}{a}}\, \cosh \left (f x +e \right ) \sqrt {a +b \sinh \left (f x +e \right )^{2}}\, f}\) \(414\)

input
int((a+b*sinh(f*x+e)^2)^(3/2)*tanh(f*x+e)^2,x,method=_RETURNVERBOSE)
 
output
-1/3*(-(-b/a)^(1/2)*b^2*sinh(f*x+e)^5+2*(-b/a)^(1/2)*a*b*sinh(f*x+e)^3-4*( 
-b/a)^(1/2)*b^2*sinh(f*x+e)^3-3*a^2*((a+b*sinh(f*x+e)^2)/a)^(1/2)*(cosh(f* 
x+e)^2)^(1/2)*EllipticF(sinh(f*x+e)*(-b/a)^(1/2),(a/b)^(1/2))+11*a*((a+b*s 
inh(f*x+e)^2)/a)^(1/2)*(cosh(f*x+e)^2)^(1/2)*EllipticF(sinh(f*x+e)*(-b/a)^ 
(1/2),(a/b)^(1/2))*b-8*((a+b*sinh(f*x+e)^2)/a)^(1/2)*(cosh(f*x+e)^2)^(1/2) 
*EllipticF(sinh(f*x+e)*(-b/a)^(1/2),(a/b)^(1/2))*b^2-7*((a+b*sinh(f*x+e)^2 
)/a)^(1/2)*(cosh(f*x+e)^2)^(1/2)*EllipticE(sinh(f*x+e)*(-b/a)^(1/2),(a/b)^ 
(1/2))*a*b+8*((a+b*sinh(f*x+e)^2)/a)^(1/2)*(cosh(f*x+e)^2)^(1/2)*EllipticE 
(sinh(f*x+e)*(-b/a)^(1/2),(a/b)^(1/2))*b^2+3*(-b/a)^(1/2)*a^2*sinh(f*x+e)- 
4*(-b/a)^(1/2)*a*b*sinh(f*x+e))/(-b/a)^(1/2)/cosh(f*x+e)/(a+b*sinh(f*x+e)^ 
2)^(1/2)/f
 
3.5.75.5 Fricas [F]

\[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\int { {\left (b \sinh \left (f x + e\right )^{2} + a\right )}^{\frac {3}{2}} \tanh \left (f x + e\right )^{2} \,d x } \]

input
integrate((a+b*sinh(f*x+e)^2)^(3/2)*tanh(f*x+e)^2,x, algorithm="fricas")
 
output
integral((b*sinh(f*x + e)^2 + a)^(3/2)*tanh(f*x + e)^2, x)
 
3.5.75.6 Sympy [F]

\[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\int \left (a + b \sinh ^{2}{\left (e + f x \right )}\right )^{\frac {3}{2}} \tanh ^{2}{\left (e + f x \right )}\, dx \]

input
integrate((a+b*sinh(f*x+e)**2)**(3/2)*tanh(f*x+e)**2,x)
 
output
Integral((a + b*sinh(e + f*x)**2)**(3/2)*tanh(e + f*x)**2, x)
 
3.5.75.7 Maxima [F]

\[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\int { {\left (b \sinh \left (f x + e\right )^{2} + a\right )}^{\frac {3}{2}} \tanh \left (f x + e\right )^{2} \,d x } \]

input
integrate((a+b*sinh(f*x+e)^2)^(3/2)*tanh(f*x+e)^2,x, algorithm="maxima")
 
output
integrate((b*sinh(f*x + e)^2 + a)^(3/2)*tanh(f*x + e)^2, x)
 
3.5.75.8 Giac [F(-2)]

Exception generated. \[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\text {Exception raised: TypeError} \]

input
integrate((a+b*sinh(f*x+e)^2)^(3/2)*tanh(f*x+e)^2,x, algorithm="giac")
 
output
Exception raised: TypeError >> an error occurred running a Giac command:IN 
PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Error: Bad Argument Type
 
3.5.75.9 Mupad [F(-1)]

Timed out. \[ \int \left (a+b \sinh ^2(e+f x)\right )^{3/2} \tanh ^2(e+f x) \, dx=\int {\mathrm {tanh}\left (e+f\,x\right )}^2\,{\left (b\,{\mathrm {sinh}\left (e+f\,x\right )}^2+a\right )}^{3/2} \,d x \]

input
int(tanh(e + f*x)^2*(a + b*sinh(e + f*x)^2)^(3/2),x)
 
output
int(tanh(e + f*x)^2*(a + b*sinh(e + f*x)^2)^(3/2), x)